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Linear Equations in Two Variables — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsLinear Equations in Two Variables2 Marks
Question
The linear equation that converts Fahrenheit $(F)$ to Celsius $(C)$ is given by the relation, $\text{C}=\frac{5\text{F}-160}{9}$ What is the numerical value of the temperature which is same in both the scales?
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Answer

$\text{C}=\frac{5\text{F}-160}{9}$ putting $C = F,$ in the given relation,
we get $\text{F}=\frac{5\text{F}-160}{9}$
​​​​​​​$\Rightarrow9\text{F}=5\text{F}-160$
$\Rightarrow4\text{F}=160$
$\therefore\text{F}=\frac{-160}{4}=-40^\circ$
Hence, the numarical value of the temperature which is same in both the scales is $-40.$

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