Question
The linear equation that converts Fahrenheit $(F)$ to Celsius $(C)$ is given by the relation, $\text{c}=\frac{5\text{F}-160}{9}$ If the temperature is $35^\circ C$, what is the temperature in Fahrenheit?
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Answer
$\text{c}=\frac{5\text{F}-160}{9}$ putting $C = 35^\circ $,
we get $35^\circ=\frac{5\text{(F)}-160}{9}\Rightarrow315^\circ=5\text{F}-160$
$\Rightarrow5\text{F}=315+160=475$
$\therefore\text{F}=\frac{475}{5}=95^\circ$
Hence, the temperature in Fahrenheit is $95^\circ F.$
we get $35^\circ=\frac{5\text{(F)}-160}{9}\Rightarrow315^\circ=5\text{F}-160$
$\Rightarrow5\text{F}=315+160=475$
$\therefore\text{F}=\frac{475}{5}=95^\circ$
Hence, the temperature in Fahrenheit is $95^\circ F.$
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