MCQ
The logical statement $(p \rightarrow q) \wedge(q \rightarrow \sim p)$ is equivalent to:
  • A
    p
  • B
    ∼q.
  • C
    q
  • ∼p

Answer

Correct option: D.
∼p
(D)
$(p \rightarrow q) \wedge(q \rightarrow \sim p)$
pq$\sim p$$p \rightarrow q$$q \rightarrow \sim p$$\begin{array}{c}(p \rightarrow q) \\ \wedge \\ (q \rightarrow \sim p)\end{array}$
TTFTFF
TFFFTF
FTTTTT
FFTTTT
$\therefore \quad(p \rightarrow q) \wedge(p \rightarrow \sim q)=\sim p$

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