MCQ
The maximum horizontal range of a projectile is $400\;m$.The maximum height atteined by it?
- ✓$100$
- B$200$
- C$400$
- D$800$
$R = 4H\cot \theta $
$\Rightarrow 400 = 4H\cot 45^\circ $
$\Rightarrow \,H = 100\,m$
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$\text{v}_\text{av}=\frac{1}2\big[\text{v}(\text{t}_1)+\text{v}(\text{t}_2)\big]$
$\text{v}_\text{av}=\frac{r(\text{t}_2)-\text{r}(\text{t}_1)}{\text{t}_2-\text{t}_1}$
$\text{r}=\frac{1}2(\text{v}(\text{t}_2)-\text{v}(\text{t}_1))(\text{t}_2-\text{t}_1)$
$\text{a}_\text{av}=\frac{\text{v}(\text{t}_2)-\text{v}(\text{t}_1)}{\text{t}_2-\text{t}_1}$

(Velocity of sound in air is $340\,ms ^{-1}$ )