MCQ
The maximum number of electrons in subshell is given by the expression :
- ✓$4l + 2$
- B$4l - 2$
- C$2l + 1$
- D$2n^2$
Thus,
$s$ - subshell $(1=0)$ contains $2$ electrons.
$p$ - subshell $(1=1)$ contains $6$ electrons.
$d$ - subshell $(1=2)$ contains $10$ electrons.
$f$ - subshell $(1=3)$ contains $14$ electrons.
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| List $-I$ (Molecule / Species) | List $-II$ |
| $(P)$ $NO_2$ (Unpaired electron in) | $(1)$ Vacant $p-$ orbital involved in hybridization |
| $(Q)$ $B_2H_6$ | $(2)$ $sp^2-$ orbital |
| $(R)$ $ClO_3$ (Unpaired electron in) | $(3)$ $sp^3-$orbital |
| $(S)$ $CH_3^+$ | $(4)$ $120^o$ Bond angle |

( electron charge $= 1.60\times10^{-19}\, C$)