MCQ
The maximum probability of finding an electron in the ${d_{xy}}$ orbital is
- AAlong the $x-$ axis
- BAlong the $y-$ axis
- ✓At an angle of ${45^o}$ from the $x$ and $y-$ axes
- DAt an angle of ${90^o}$ from the $x$ and $y-$ axes
So, the finding electron in a $d _{ xy }$ orbital is maximum at an angle of $45$ degree from $x$ and $y$ axis.
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$2Zn + {O_2} \to 2ZnO;\Delta H = - 412\,J$