MCQ
The maximum value of $sin(cos\,(tan\,x))$ is
- A$\frac {\sqrt 3}{2}$
- ✓$sin\,1$
- C$1$
- D$sin\,(cos\,1)$
So, sine function is increasing in between $[-1,1],$ so maximum value of $\sin (\cos (\tan x))$ is $\sin 1.$
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$(1,1)(-1,1),(1,-1),(-1,-1),(-2,1)(2,-1),(-1,2)$ and $(-2,-1)$