The mean of first five prime numbers is: - Vidyadip

MCQ

The mean of first five prime numbers is:

A
3
B
3.6
C
7
D
7

✓

Answer

5.6

Solution:

The first five prime numbers are 2, 3, 5, 7, 11

$\text{Mean}=\frac{\text{sum of the terms}}{\text{no. of terms}}$

$\text{Mean}=\frac{2+3+5+7+11}{5}$

$=\frac{28}{5}=5.6$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Statistics→Statistics — all question types→MATHS STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

For the ellipse $12\text{x}^2+4\text{y}^2+24\text{x}-16\text{y}+25=0$

IF A = [5, 6, 7] and B = [7, 8, 9] then $\text{A }\cup \text{ B}$ is equal to.

Choose the correct answer.

Given the integers r > 1, n > 2, and coefficients of (3r)^th and (r + 2)^nd terms in the binomial expansion of (1 + x)²ⁿ are equal, then:

What is the distance between the points (2, -1, 3) and (-2, 1, 3):

Choose the correct answer.
The number of different four digit numbers that can be formed with the digits 2, 3, 4, 7 and using each digit only once is

If $\alpha,\beta$ are the roots of the equation x²− p(x + 1) − c = 0, then $(\alpha+1)(\beta+1)=$

If $5\sin\alpha=3\sin(\alpha+2\beta)\not=0,$ then $\tan(\alpha+\beta)$ is equal to:

$2\tan\beta$
$3\tan\beta$
$4\tan\beta$
$6\tan\beta$

The sum of the coefficients in the expansion of (1 - x)¹⁰

If $y =1+\frac{x}{1!}+\frac{x^2}{2!}+\frac{x^3}{3!}+\ldots$, then $\frac{d y}{d x}=$

The coordinates of the foot of the perpendicular from the point (2, 3) on the line x + y - 11 = 0 are:

(-6, 5)
(5, 6)
(-5, 6)
(6, 5)