MCQ
The minimum orbital angular momentum of the electron in a hydrogen atom is:
- A$\text{h}$
- B$\frac{\text{h}}{2}$
- ✓$\frac{\text{h}}{2\pi}$
- D$\frac{\text{h}}{\lambda}$
✓
Answer
Correct option: C.
$\frac{\text{h}}{2\pi}$
According to Bohr's atomic theory, the orbital angular momentum of an electron is an integral multiplt of $\frac{\text{h}}{2\pi}$
$\therefore\ \text{L}_\text{n}=\frac{\text{nh}}{2\pi}$
Here,
n = Principal quantum number
The minimum of n is 1
Thus, the minimum value of the orbit angular momentum of the electron in a hydrogen is given by $\text{L}=\frac{\text{h}}{2\pi}$
$\therefore\ \text{L}_\text{n}=\frac{\text{nh}}{2\pi}$
Here,
n = Principal quantum number
The minimum of n is 1
Thus, the minimum value of the orbit angular momentum of the electron in a hydrogen is given by $\text{L}=\frac{\text{h}}{2\pi}$
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