MCQ
The minimum value of $(8sec^2 \theta + 2cos^2 \theta)$ is equal to :-
  • $10$
  • B
    $16$
  • C
    $8$
  • D
    None

Answer

Correct option: A.
$10$
a
Minimum value occurs
at $\theta = 0^o$
$8 + 2 = 10$

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