MCQ
The molecular formula of felspar is
- ✓${K_2}O\,.\,A{l_2}{O_3}.\,6Si{O_2}$
- B${K_2}O\,.\,3A{l_2}{O_3}.\,6Si{O_2}$
- C$N{a_3}Al{F_6}$
- D$CaS{O_4}.\,2{H_2}O$
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This reaction was studied at $-10^{\circ} C$ and the following data was obtained
| run | $[ NO ]_{0}$ | $\left[ Cl _{2}\right]_{0}$ | $r _{0}$ |
| $1$ | $0.10$ | $0.10$ | $0.18$ |
| $2$ | $0.10$ | $0.20$ | $0.35$ |
| $3$ | $0.20$ | $0.20$ | $1.40$ |
$[ NO ]_{0}$ and $\left[ Cl _{2}\right]_{0}$ are the initial concentrations and $r _{0}$ is the initial reaction rate.
The overall order of the reaction is ..........
(Round off to the Nearest Integer).
Comment on optical activity of the products

(Given : $h =6.63 \times 10^{-34} \,Js$ and $c =3.08 \times 10^{8} \,ms ^{-1}$ )
$A$. $Al^{3+}$ $B$. $Cu^{2+}$ $C$. $Ba^{2+}$ $D$. $Co^{2+}$ $E$. $Mg^{2+}$
Choose the correct answer from the options given below.