MCQ
The molecule which is pyramid shape is
- ✓$PC{l_3}$
- B$CO_3^{2 - }$
- C$S{O_3}$
- D$NO_3^ - $
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$(I)\,\,\,\,{N_2} + 2{O_2} \rightleftharpoons 2N{O_2}$
$(II)\,\,\,\,2N{O_2} \rightleftharpoons {N_2} + 2{O_2}$
$(III)\,\,\,\,N{O_2} \rightleftharpoons \frac{1}{2}{N_2} + 2{O_2}$
The correct relation from the following is
$(I)\,C{H_3}O\mathop C\limits^ \oplus {H_2}$ is more stable than $C{H_3}\mathop C\limits^ \oplus {H_2}$
$(II)\,M{e_2}\mathop C\limits^ \oplus H$ is more stable than $C{H_3}C{H_2}\mathop C\limits^ \oplus {H_2}$
$(III)\,C{H_2} = CH - \mathop C\limits^ \oplus {H_2}$ is more stable than $C{H_3}C{H_2}\mathop C\limits^ \oplus {H_2}$
$(IV)\,C{H_2} = \mathop C\limits^ \oplus H$ is more stable than $C{H_3}\mathop C\limits^ \oplus {H_2}$
At $300 \,K$, ozone is fifty percent dissociated. The standard free energy change at this temperature and $1\, atm$ pressure is $(-)$ $........\,J\, mol ^{-1}$ (Nearest integer)
[Given: $\ln 1.35=0.3$ and $R =8.3 J K ^{-1} mol ^{-1}$ ]
Assertion $(A) :$ Metallic character decreases and non-metallic character increases on moving from left to right in a period.
Reason $(R)$ $:$ It is due to increase in ionisation enthalpy and decrease in electron gain enthalpy, when one moves from left to right in a period.
In the light of the above statements, choose the most appropriate answer from the options given below :