MCQ
The most basic oxide of elements in group $14$ of the periodic table is
- A$SiO_2$
- B$GrO$
- C$SnO_2$
- ✓$PbO$
Lead also form an oxide $Pb _3 O _4$ which is a mixed oxide of $PbO$ and $PbO 2$. Among the monoxides, $CO$ is neutral, $GeO$ is basic while $SnO$ and $PbO$ are amphoteric.
In $CO_2$, $C$ is sp hybridised
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$2S{O_2} + {O_2}$ $\rightleftharpoons$ $2S{O_3};\,\,\Delta H = - 45.2\,kcal$ Which of the following factors favours the formation of $S{O_3}$
(Atomic no. $Ti = 22, V = 23, Cr = 24, Fe = 26$)
[Given : $R_{\mathrm{H}}\left(\right.$ Rydberg constant) $=2.18 \times 10^{-18} \mathrm{~J}$.
$h($ Plank's constant $)=6.6 \times 10^{-34}$ J.s. $]$