MCQ
The most commonly used reducing agent is:
- A$\mathrm{AlCl}_3$
- B$\mathrm{PbCl}_2$.
- C$\mathrm{SnCl}_4$.
- ✓$\mathrm{SnCl}_2$
✓
Answer
Correct option: D.
$\mathrm{SnCl}_2$
$+4$ oxidation state of $Sn$ is more stable than $+2$ oxidation state. Therefore, $\ce{Sn^{2+}}$ can be easily oxidised to $\ce{Sn^{4+}}$ and hence $\ce{SnCl_2}$ acts a reducing agent.
$\text{SnCl}_2+2\text{Cl}\rightarrow\text{SnCl}_4+2\text{e}^-$
$\text{SnCl}_2+2\text{Cl}\rightarrow\text{SnCl}_4+2\text{e}^-$
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