MCQ
The most frequent value in a data set is?
  • A
    Median
  • Mode
  • C
    Arithmetic mean
  • D
    Geometric mean

Answer

Correct option: B.
Mode
Mode is the highest occurring figure in a series.
It is the value in a series of observation that repeats maximum number of times and, which represents the whole series as most of the values, in the series revolves around this value.
Therefore, mode is the value that occurs the most frequent times in a series.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Let in a series of $2 n$ observations, half of them are equal to $a$ and remaining half are equal to $-a.$ Also by adding a constant $b$ in each of these observations, the mean and standard deviation of new set become $5$ and $20 ,$ respectively. Then the value of $a^{2}+b^{2}$ is equal to ....... .
The propositions (p ⇒ ~p) Λ (~p ⇒ p) is.
Let $L$ is distance between two parallel normals of  , $\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1,\,\,\,a > b$ then maximum value of $L$ is
If (-4, 5) is one vertex and 7x - y + 8 = 0 is onediagonal of a square, then the equation of second diagonal is:
Let set M = { x, 2x, 4x } for any number x. If the average (arithmetic mean) of the numbers in set M is 14, find the value of x:
In a series of $2n$ observations, half of them equal to $a$ and remaining half equal to $-a$. If the standard deviation of the observations is $2$, then $|a|$ equals
If the circle ${(x - h)^2} + {(y - k)^2} = {r^2}$ touches the curve $y = {x^2} + 1$ at a point $(1, 2)$, then the possible locations of the points $(h, k)$ are given by
If arg (z – 1) = arg (z + 3i), then x – 1 : y is equal to:
If at least one value of the complex number $z = x + iy$ satisfy the condition $|z + \sqrt 2 | = {a^2} - 3a + 2$ and the inequality $|z + i\sqrt 2 |\, < \, {a^2}$, then
If $\left| {\,\begin{array}{*{20}{c}}{\cos (A + B)}&{ - \sin (A + B)}&{\cos 2B}\\{\sin A}&{\cos A}&{\sin B}\\{ - \cos A}&{\sin A}&{\cos B}\end{array}\,} \right| = 0$, then $B =$