Question
The most stable conformation of $n-$ butane is
Staggard form is most stable because of minimum repulsion between bulky methyl groups.
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|
${List-I }$ ${(Reactants) }$ |
${List-II }$ ${ Products }$ |
| ($A$)Phenol, $\mathrm{Zn} / \Delta$ |
$(I)$ Salicylaldehyde |
| ($B$)Phenol, $\mathrm{CHCl}_3, \mathrm{NaOH}, \mathrm{HCl}$ |
$(II)$ Salicylic acid |
| ($C$)Phenol, $\mathrm{CO}_2, \mathrm{NaOH}, \mathrm{HCl}$ |
$(III)$ Benzene |
| ($D$)Phenol, Conc. $\mathrm{HNO}_3$ |
$(IV)$ Picric acid |
$Mn^{2+} + 2e^- \rightarrow Mn,\, $$E^o = - 1.18\, V$
$Mn^{2+} \rightarrow Mn^{3+} + e^-,$ $ E^o = - 1.51 \,V$
The $E^o$ for the reaction $3Mn^{2+} \rightarrow Mn^o + 2Mn^{3+},$
and possibility of the forward reaction are respectively