MCQ
The most suitable reagent for the given conversion is


- A$LiAlH_4$
- B$NaBH_4$
- C$H_2/Pd$
- ✓$B_2H_6$


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$MnO _{4}^{-}+8 H ^{+}+5 e ^{-} \rightarrow Mn ^{2+}+4 H _{2} O , E ^{\circ}=1.51 V$
The quantity of electricity required in Faraday to reduce five moles of $MnO _{4}^{-}$ is ..... .
$\left[\text { Given }: E _{ Ag ^{+} / Ag }^{\Theta}=0.80 V \text { and } \frac{2.303 \,RT }{ F }=0.06\,V \right]$