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Electromagnetic Induction — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsElectromagnetic Induction1 Mark
MCQ
The mutual inductance between two coils is $1.25$ henry. If the current in the primary changes at the rate of $80$ ampere/second, then the induced e.m.f. in the secondary is
  • A
    $12.5 \mathrm{~V}$
  • B
    $64.0 \mathrm{~V}$
  • C
    $0.016 \mathrm{~V}$
  • ✓
    $100.0 \mathrm{~V}$
✓

Answer

Correct option: D.
$100.0 \mathrm{~V}$
(d) $e=M \frac{d i}{d t}=1.25 \times 80=100 \mathrm{~V}$

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