- A$N{O_2}$
- B$N{O_3}$
- C$NO$
- ✓$NO_2^ + $
$HON{O_2} + 2{H_2}S{O_4}$ $ \rightleftharpoons $ ${H_3}{O^ + } + 2HSO_4^ - + \mathop {NO_2^ + }\limits_{({\rm{nitronium ion}})} $
The electrophile responsible for nitration is $NO_2^ + $ ion.
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True statement about sequence on the basis of assumption that $R$ contains $3$ different groups is
$\mathop R\limits^{\delta \oplus } \,\mathop {Br}\limits^{\delta \,\Theta } \, \rightleftharpoons $ $\mathop {\boxed{{R^ \oplus }B{r^\Theta }}}\limits_{(a)} \,\,\, \rightleftharpoons \,$$\,\mathop {\boxed{{R^ \oplus }}\,\boxed{B{r^\Theta }}\,}\limits_{(b)} \,\, \rightleftharpoons $ ${\boxed{{R^ \oplus }}}$ $ \rightleftharpoons $ $\mathop {\,\boxed{B{r^\Theta }}\,}\limits_{(c)} \,$
($A$) $\mathrm{BrF}_5$ ($B$) $\mathrm{ClF}_3$ ($C$) $\mathrm{XeF}_4$ ($D$) $\mathrm{SF}_4$
The correct statement is
(Round of to the Nearest Integer).
(Given : $\left. R =8.314\, J\, mol ^{-1} K ^{-1}\right)$