MCQ
The normality of $10\,lit.$ volume hydrogen peroxide is
  • A
    $0.176$
  • B
    $3.52$
  • $1.78$
  • D
    $0.88$

Answer

Correct option: C.
$1.78$
c
(c) ${H_2}{O_2} \to {H_2}O + \frac{1}{2}{O_2}$

$1 M$  ${H_2}{O_2}$solution $ = 2N = 34\,gm/litre = 11.2$

So Normality $ = \frac{{2 \times 10}}{{11.2}} = 1.78$

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