- A$0.176$
- B$3.52$
- ✓$1.78$
- D$0.88$
$1 M$ ${H_2}{O_2}$solution $ = 2N = 34\,gm/litre = 11.2$
So Normality $ = \frac{{2 \times 10}}{{11.2}} = 1.78$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(I)$ It is easier to remove $2 \mathrm{p}$ electron than $2 \mathrm{s}$ electron
$(II)$ $2 \mathrm{p}$ electron of $\mathrm{B}$ is more shielded from the nucleus by the inner core of electrons than the $2 s$ electrons of $Be.$
$(III)\; 2 s$ electron has more penetration power than $2 \mathrm{p}$ electron.
$(IV)$ atomic radius of $\mathrm{B}$ is more than $\mathrm{Be}$
(Atomic number $\mathrm{B}=5, \mathrm{Be}=4$ )
The correct statements are
Compound $(C)$ is
Assertion $(A)$: Among group $13$ elements, boron's melting point is unusually high $(2453 \mathrm{~K})$.
Reason $(R):$ Solid boron has a strong crystalline lattice.
In the context of the above statements, choose the correct answer from the following options:
How many geometrical isomers are possible for this compound?