MCQ
The normality of $2.3\,M$ ${H_2}S{O_4}$ solution is ...... $N$
- A$2.3$
- ✓$4.6$
- C$0.46$
- D$0.23$
✓
Answer
Correct option: B.
$4.6$
b
(b) Normality of $2.3\,M\,{H_2}S{O_4} = M \times $ Valency $ = 2.3 \times 2 = 4.6N$
(b) Normality of $2.3\,M\,{H_2}S{O_4} = M \times $ Valency $ = 2.3 \times 2 = 4.6N$
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