MCQ
The number of different possible orders of matrices having $18$ identical elements is:
  • A
    $3$
  • B
    $1$
  • $6$
  • D
    $4$

Answer

Correct option: C.
$6$
Let the order of the matrix is $ (\text{a}\times\text{b})$ There are $18$ elements in the matrix.
So, $\text{a}\times\text{b} = 18$
Possible orders can be $ (1\times18),( 18\times1),( 2\times9),( 9\times2),( 3\times6),( 6\times3)$
There are $6$ possible orders.

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