MCQ
The number of line segments determined by three non-collinear points is:
- A$0$
- ✓$3$
- C$1$
- D$2$
✓
Answer
Correct option: B.
$3$
You need two points to draw a line segment. If the points $A, B$ and are non-collinear, we can draw the lines: $A B, A C$, $B A, B C, C A, C B$. Now, line $A B$ is the same as line $B A$, same for lines $A C$ and $C A$ and $B C$ and $C B$. So, the lines are $A B, B C$, and $AC 3$ lines only.
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