MCQ
The number of spherical bullets each $5\ dm$ in diameter which can be cast from a rectangular block of lead $11m$ long, $10m$ broad and $5$ high is:
- A$5600.$
- B$6300.$
- ✓$8400.$
- D$4200.$
Here, radius of spherical bullets $= 2.5\ dm$ or $0.25\ m(1\ dm = 0.1\ m)$
Let the number of bullets be $n$
Now, volume of n number of bullets $=$ volume of rectangular block
$\text{n}\times\frac{4}{3}\pi\text{r}^3=\text{l}\times\text{b}\times\text{h}$
$\text{n}\times\frac{4}{3}\times\frac{22}{7}\times0.25\times0.25\times0.25=11\times10\times5$
$\text{n}=\frac{11\times10\times5\times21}{88\times0.25\times0.25\times0.25}$
$\text{n}=8400$
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