Question
The number of structural isomers for $\mathrm{C}_6 \mathrm{H}_{14}$ is

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$\Delta_{ I } G ^{\circ}=-9.478\, kJ\, mol ^{-1}$
If we start the reaction in a closed container at $495\, K$ with $22$ millimoles of $A ,$ the amount of $B$ is the equilibrium mixture is millimoles ..............
(Round off to the Nearest Integer).
$\left[ R =8.314 J mol ^{-1} K ^{-1} ; \ell n 10=2.303\right]$
Reason : Actual structure of benzene is a hybrid of following two structures.
$\underset{({{C}_{2}}{{H}_{6}}O)}{\mathop{X}}\,\,\xrightarrow[573\,\,K]{Cu}$ $A$ $\xrightarrow[^{-}OH\,,\,\Delta ]{{{[Ag{{(N{{H}_{3}})}_{2}}]}^{+}}}$ Silver mirror
$A\,\xrightarrow{^{-}OH\,,\,\Delta }Y$
$A\,\xrightarrow{N{{H}_{2}}NHCON{{H}_{2}}}Z$