MCQ
The number of structural isomers possible for the molecular formula $C_4H_8F_2$ are
- A$7$
- ✓$9$
- C$11$
- D$8$

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$C{H_3} - C \equiv C - C{H_3}\xrightarrow{{{H_2}/Pd - BaS{O_4}}}$ $A\xrightarrow{{B{r_2}/CC{l_4}}}C$
$C{H_3} - C \equiv C - C{H_3}\xrightarrow{{Na/Liq.\,N{H_3}}}$ $B\xrightarrow{{B{r_2}/{H_2}O}}D$
$Ba{\left( {{N_3}} \right)_2}\xrightarrow{\Delta }Ba + {N_2} \uparrow $