MCQ
The numbers $(\sqrt 2 + 1),\;1,\;(\sqrt 2 - 1)$ will be in
  • A
    $A.P.$
  • $G.P.$
  • C
    $H.P.$
  • D
    None of these

Answer

Correct option: B.
$G.P.$
b
(b) The numbers $(\sqrt 2 + 1),\;1,\;(\sqrt 2 - 1)$ will be in $G.P.$

$\therefore $ ${(1)^2} = (\sqrt 2 + 1)(\sqrt 2 - 1) = {(\sqrt 2 )^2} - {(1)^2} = 2 - 1 = 1$.

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