- A$2HI \to {H_2} + {I_2}$
- ✓${N_2}{O_5} \to {N_2}{O_4} + \frac{1}{2}{O_2}$
- C${H_2} + C{l_2} \to 2HCl$
- D$PC{l_3} + C{l_2} \to PC{l_5}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}} \\
| \\
{C{H_3} - C - ONa} \\
| \\
{\,\,\,\,\,C{H_3}}
\end{array}\, + \,C{H_3}C{H_2}Cl\,\xrightarrow{{ - NaCl}}\,$ $\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - O - C{H_2} - C{H_3}} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
is called


If one Faraday of electricity is passed through the battery during the charging, the number of moles of $Cr^{3+}$ removed from the solution is