MCQ
The orbital angular momentum of a $p-$ electron is given as
- ✓$\frac{h}{\sqrt{2} \pi }$
- B$\sqrt{3}$ $\frac{h}{2 \pi }$
- C$\sqrt{\frac{3}{2}}$ $\frac{h}{\pi}$
- D$\sqrt{6}$ $\frac{h}{2 \pi }$
$\therefore$ For p-electron, $l=1$
$\therefore$ Orbital angular momentum,
$=\sqrt{1(1+1)} \times \frac{h}{2 \pi}$
$=\sqrt{2} \times \frac{h}{2 \pi}$
$=\frac{h}{\sqrt{2} \pi}$
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Its bond order is