MCQ
The oxidation number of carbon in $\mathrm{CH}_2 \mathrm{Cl}_2$ is
- ✓$0$
- B$2$
- C$3$
- D$5$
✓
Answer
Correct option: A.
$0$
Let $x$ be the oxidation state of $C$ in $\mathrm{CH}_2 \mathrm{Cl}_2$.
Since the overall charge on the complex is $0$, the sum of oxidation states of all elements in it should be equal to $0$.
Therefore, $x + 2 + 2(−1) = 0$
Since the overall charge on the complex is $0$, the sum of oxidation states of all elements in it should be equal to $0$.
Therefore, $x + 2 + 2(−1) = 0$
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