MCQ
The oxidation number of carbon in CH2Cl2 is
- A0
- B2
- C3
- D5
Explanation:
Let x be the oxidation state of C in CH2Cl2.
Since the overall charge on the complex is 0, the sum of oxidation states of all elements in it should be equal to 0.
Therefore, x + 2 + 2(−1) = 0
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$(A)$ Pentane
$(B)\,2-$ Methyl butane
$(C)\,2,2-$ Dimethyl propane
