MCQ
The oxidation number of chlorine is maximum in $.........$
- A$\ce{HOCl}$
- B$ \mathrm{Cl}_2 \mathrm{O}_6 $
- ✓$ \mathrm{KClO}_4 $
- D$\mathrm{NaClO}_3 $
✓
Answer
Correct option: C.
$ \mathrm{KClO}_4 $
The oxidation numbers of chlorine in $\ce{HOCl},\ \mathrm{Cl}_2 \mathrm{O}_6 ,\ \mathrm{KClO}_4 $
and $\ce{NaClO3}$ are $+1, +6, +7$ and $+5$ respectively. Hence, the oxidation number of chlorine is maximum in $ \mathrm{KClO}_4 $
.
and $\ce{NaClO3}$ are $+1, +6, +7$ and $+5$ respectively. Hence, the oxidation number of chlorine is maximum in $ \mathrm{KClO}_4 $
.
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