MCQ
The oxidation number of Cl in CaOCl2 is:
- A−1 and +1
- B+2
- C−2
- DNone
Explanation:
In the given compound CaOCl2, one Cl is directly attached to Ca and other to O.
OCl⊖: −2 + x = −1 ⇒ x = +1
Cl⊖: −1
Oxidation states of Cl are −1 and +1.
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$NO_2^ + \to N{O_2} \to NO_2^ - $