MCQ
The oxidation number of $S$ in ${H_2}{S_2}{O_8}$ is
- A$+2$
- B$+4$
- ✓$+6$
- D$+7$
✓
Answer
Correct option: C.
$+6$
(c)The chemical structure of ${H_2}{S_2}{O_8}$ is as follows
$H - O - \mathop {\mathop S\limits_{||}^{||} }\limits_O^O - O - O - \mathop {\mathop S\limits_{||}^{||} }\limits_O^O - O - H$
:-So the oxidation number of S should be :$\mathop {2 \times ( + 1)}\limits_{({\rm{for}}\,\,H)} + \mathop {2 \times X}\limits_{({\rm{for}}\,\,S)} + \mathop {6 \times ( - 2)}\limits_{({\rm{for}}\,\,O)} + \mathop {2 \times ( - 1)}\limits_{({\rm{for}}\,\,O - O)} = 0$ or $X = + 6$.
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