MCQ
The oxidation state of $\text{Cr}$ in $\text{CrO}_5$, is:
- A$+10$
- B$+5$
- ✓$+6$
- D$+3$
✓
Answer
Correct option: C.
$+6$
There are two Peroxide linkage $\text{O}^{2-}_2$
$\because$ Oxidation state is $x - 1 - 1 - 1 - 1 - 2 = 0$
$x = +6$
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