MCQ
The oxidation state of Cr in CrO5, is:
- A+10
- B+5
- C+6
- D+3
✓
Answer
- +6
Explanation:
There are two Peroxide linkage
$\text{O}^{2-}_2$$\because$ Oxidation state is x - 1 - 1 - 1 - 1 - 2 = 0
x = +6
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