MCQ
The oxidation state of $Fe$ in ${K_4}[Fe{(CN)_6}]$ is
- ✓$2$
- B$-2$
- C$3$
- D$4$
✓
Answer
Correct option: A.
$2$
a
(a) $4 \times ( + 1) + x + 6 \times - 1 = 0$
(a) $4 \times ( + 1) + x + 6 \times - 1 = 0$
or $x = + 6 - 4 = + 2$
Oxidation state of $Fe = + 2$
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