MCQ
The oxidation state of $Fe$ in ${K_4}[Fe{(CN)_6}]$ is
- ✓$2$
- B$-2$
- C$3$
- D$4$
or $x = + 6 - 4 = + 2$
Oxidation state of $Fe = + 2$
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$(A)$ $E_a = 0$
$(B)$ $T$ $=$ $\infty $
$(C)$ $T = 0$
$(D)$ $E_a$ $=$ $\infty $
$A$. $\mathrm{Ti}^{3+}$ $B$. $\mathrm{Cr}^{2+}$ $C$. $\mathrm{Mn}^{2+}$ $D$.$\mathrm{Fe}^{2+}$ $E$. $\mathrm{Sc}^{3+}$
Choose the most appropriate answer from the options given below.
Product $(B)$ of above the reaction is
Sucrose $\quad$ $\quad$ $\quad$ $\quad$ $\quad$ $\quad$ $\quad$ Glucose $\quad$ Fructose
$C _{6} H _{12} O _{6} \stackrel{\text { Enzyme B }}{\longrightarrow} 2 C _{2} H _{5} OH +2 CO _{2}$
Glucose
In the above reactions, the enzyme $A$ and enzyme $B$ respectively are :-