MCQ
The oxidation state of nitrogen in NaNO3 is:
- A+3
- B+5
- C−4
- D−5
Explanation:
The overall charge is zero (because it is not an ion). Since sodium is a 1A family member, the charge is +1.
The charge of oxygen is almost always -2.
Hence, 1 + OS of N + (3 × −2) = 0
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| Item $I$ | Item $II$ |
| $(a)$ Benzaldehyde | $(p)$ Mobile phase |
| $(b)$ Alumina | $(q)$ Adsorbent |
| $(c)$ Acetonitrile | $(r)$ Adsorbate |
