MCQ
The oxidation state of sulphur in $SO_4^{2 - }$ is
- A$4$
- B$2$
- ✓$6$
- D$-6$
$x - 2 \times 4 = - 2$
$x = 8 - 2 = + 6$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

$CH_3 - CH_3, CH_3 - CH_2 $$- CH_3, (CH_3)_2CH - CH_3,$
$ CH_3 - CH_2 - CH(CH_3)_2.$
Increasing order of stability of the radicals is
