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Statement $I:$ The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole - dipole interactions.
Statement $II:$ The boiling points of aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of $H$-bonding.
In the light of the above statements, choose the most appropriate answer from the options given below :
| $p ( mm Hg )$ | $50$ | $100$ | $200$ | $400$ |
| Relative $t _{1 / 2}( s )$ | $4$ | $2$ | $1$ | $0.5$ |
The order of the reaction is
$(i)$ $PCl_3 + 3H_2O \to H_3PO_3 + 3HCl$
$(ii)$ $SF_4 + 3H_2O \to H_3SO_3 + 4HF$
$(iii)$ $BCI_3 + 3H_2O \to H_3BO_3 + 3HCl$
$(IV)$ $XeF_6 + 3H_2O \to XeO_3 + 6HF$
Then according to given information the incorrect statement is
$(I)$ $1\, M$ glucose $(aq.)$
$(II)$ $1\, M$ sodium chloride $(aq.)$
$(III)$ $1\, M$ acetic acid in benzene
$(IV)$ $1\, M$ ammonium phosphate $(aq.)$
