MCQ
The pair of ions having same electronic configuration is $ ..........$
  • A
    $\mathrm{Cr}^{3+}, \mathrm{Fe}^{3+}$
  • $\mathrm{Fe}^{3+}, \mathrm{Mn}^{2+}$
  • C
    $\mathrm{Fe}^{3+}, \mathrm{Co}^{3+}$
  • D
    $\mathrm{Sc}^{3+}, \mathrm{Cr}^{3+}$.

Answer

Correct option: B.
$\mathrm{Fe}^{3+}, \mathrm{Mn}^{2+}$
$ \mathrm{Cr}^{3+}(Z=24)=[\mathrm{Ar}] 3 \mathrm{~d}^3 $
$ \mathrm{Fe}^{3+}(\mathrm{Z}=26)=[\mathrm{Ar}] 3 \mathrm{d}^5 $
$ \mathrm{Mn}^{2+}(\mathrm{Z}=25)=[\mathrm{Ar}] 3 \mathrm{d}^5$
$ \mathrm{Co}^{3+}(\mathrm{Z}=27)=[\mathrm{Ar}] 3 \mathrm{d}^6 $
$ \mathrm{Sc}^{3+}(\mathrm{Z}=21)=[\mathrm{Ar}] 3 \mathrm{d}^0$
$\ce{Fe^{3+}}$ and $\ce{Mn^{2+}}$ will have the same number of electrons,
i.e., $23$ and, hence, have the same electronic configuration.

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