MCQ
The path of difference between two interfering waves at a point on the screen is $\frac{\lambda}{8}$. The ratio of intensity at this point and that at the central fringe will be
- ✓$0.853$
- B$8.53$
- C$85.3$
- D$853$
✓
Answer
Correct option: A.
$0.853$
a
Phase difference $=\frac{2 \pi}{\lambda}$ (Path difference)
Phase difference $=\frac{2 \pi}{\lambda}$ (Path difference)
$\Delta \phi=\frac{2 \pi}{\lambda} \cdot \frac{\lambda}{8}=\frac{\pi}{4}$
$\Gamma=I+I+2 I \cos \frac{\pi}{4}=(2+\sqrt{2}) I$
$I^{\prime \prime}=(a+a)^{2}=4 I$
$\frac{I}{{{I^\prime }^\prime }} = \frac{{2 + 1 \cdot 41}}{4} = \frac{{3 \cdot 14}}{4} = 0 \cdot 853$
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