MCQ
The $pH$ of $0.01\; M \;NaOH (aq)$ solution will be
- A$7.01$
- B$2$
- ✓$12$
- D$9$
$\mathrm{So},\left[\mathrm{OH}^{-}\right]=\mathrm{N}=10^{-2} \mathrm{N}$
$\mathrm{pOH}=-\log \left[\mathrm{OH}^{-}\right]=-\log 10^{-2}=2$
$\mathrm{pH}=14-\mathrm{pOH}=14-2$
$\mathrm{pH}=12$
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(Given: Molar mass of $Ag$ is $108\, g \,mol ^{-1}$ and that of $Cl$ is $35.5 \,g\, mol ^{-1}$ )
