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Ionic Equilibrium — Chemistry STD 12 — Question

Tamilnadu BoardEnglish MediumSTD 12ChemistryIonic Equilibrium1 Mark
MCQ
The pH of $10^{-5}$ M KOH solution will be ____________.
  • ✓
    9
  • B
    5
  • C
    19
  • D
    none of these
✓

Answer

Correct option: A.
9
The pH of $10^{-5}$ M KOH solution will be 9.
Explanation:
$\underset{10^{-5} m }{ KOH } \longrightarrow \underset{10^{-5} m }{ K ^{+}}+\underset{10^{-5} m }{ OH ^{-}}$
$[OH^-] = 10^{-5}M$
$pH = 14 – pOH$
$pH = 14 – (– log [OH^-])$
$= 14 + log [OH^-]$
$= 14 + log 10^{-5}$
$= 14 – 5$
$= 9$

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