MCQ
The $pH$ of a ${10^{ - 10}}$ molar $HCl$ solution is approximately
- A$10$
- ✓$7$
- C$1$
- D$14$
Total $[{H^ + }] = {10^{ - 7}} + {10^{ - 10}}$
$ = {10^{ - 7}} + (1 + {10^{ - 3}}) = {10^{ - 7}}(1.001)$
That is why $pH = 7$(slightly less than $7$)
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$\left( I \right)A + {e^ - } \to {A^\circleddash }\,\,\,\,\,\,{E^o} = + 0.24\,V$
$\left( {II} \right){B^ - } + {e^ - } \to {B^{ - 2}}\,\,\,\,\,\,{E^o} = + 1.25\,V$
$\left( {III} \right){C^ - } + 2{e^ - } \to {C^{ - 3}}\,\,\,\,\,\,{E^o} = + 0.15\,V$
$\left( {IV} \right)D + 2{e^ - } \to {D^{ - 2}}\,\,\,\,\,\,{E^o} = + 0.68\,V$