MCQ
The $pH$ of a solution in which the $[{H^ + }] = 0.01,$ is
- ✓$2$
- B$1$
- C$4$
- D$3$
$pH = - \log \,\,[{10^{ - 2}}]$;$pH = 2$
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| Catalyst | Process |
| $(i) \;\mathrm{Na}_{2} \mathrm{O}$ | $(a)$ The oxidation of ethyne to ethanal |
| $(ii) \;\mathrm{TiCl}_{4}+ \mathrm{Al(CH_3)}_{3}$ | $(b)$ Polymerisation of alkynes |
|
$(iii)\;\mathrm{PdCl_2} $ |
$(c)$ Oxidation of $SO_2$ in the manufacture of $H_2SO_4$ |
| $(iv)\;$Nickel complexes | $(d)$ Polymerisation of ethylene |
Which of the following is the correct option ?
$(I)$ $\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - Cl} \\
{\,\,|} \\
{\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow[{5\% \,\,water}]{{95\% \,\,\,acetone}}\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - OH} \\
| \\
{\,\,\,\,\,\,C{H_3}}
\end{array}$
$(II)$ $\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - Cl} \\
{\,\,|} \\
{\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow[{10\% \,\,water}]{{90\% \,\,\,acetone}}\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - OH} \\
| \\
{\,\,\,\,\,\,C{H_3}}
\end{array}$
$(III)$ $\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - Cl} \\
{\,\,|} \\
{\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow[{20\% \,\,water}]{{80\% \,\,\,acetone}}\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - OH} \\
| \\
{\,\,\,\,\,\,C{H_3}}
\end{array}$
$(IV)$ $\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - Cl} \\
{\,\,|} \\
{\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow{{100\% \,water}}\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - OH} \\
| \\
{\,\,\,\,\,\,C{H_3}}
\end{array}$
Arrange these reactions in decreasing order of greater proportion of inverted product and select correct answer from the codes given below :
$C{H_3} - C \equiv CH\xrightarrow[{Dry\,ether}]{{C{H_3}MgBr}}C{H_4} + (A)\xrightarrow[{(ii)\,{H_2}O/{H^ + }}]{{(ii)\,C{O_2}}}(B),(B)$ will be
correct statement is