MCQ
The $pH$ of solution having $[O{H^ - }] = {10^{ - 7}}$ is
- ✓$7$
- B$14$
- C$0$
- D$ - 7$
$\because \,[O{H^ - }] = {10^{ - 7}}$
$pOH = 7$
$\therefore \,pH = 14 - 7 = 7$.
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$I . C H_{3}^{+}$ $II.$ $H_{3} O ^{+}$ $III.$ $N H_{3}$ $I V\,\, C H_{3}^{-}$
$(1)$ $C{H_3}C{H_2}N{H_2}$ $(2)$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2}C{H_3}}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,}\\
{\,C{H_3}C{H_2}NH\,\,\,\,\,\,\,}
\end{array}$
$(3)$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}}\\
{\,|}\\
{{H_3}C - N - C{H_3}}
\end{array}$ $(4)$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}}\\
{\,|}\\
{Ph - N - H}
\end{array}$

