The phase difference between the flux linked with a coil rotating… - Vidyadip

MCQ

The phase difference between the flux linked with a coil rotating in a uniform magnetic field and induced $e.m.f.$ produce in it is

A
$\pi$
✓
$\pi / 2$
C
$\pi / 3$
D
$-\pi / 6$

✓

Answer

Correct option: B.

$\pi / 2$

b
(b) $\phi = BA\cos \theta $ where $\theta$ is the angle between area and field
$e = \frac{{ - d\phi }}{{dt}} = - BA\sin \theta .\frac{{d\theta }}{{dt}} = BA\left( {\frac{{d\theta }}{{dt}}} \right)\,\cos (90 + \theta )$
Here phase difference $= 90^o$.

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