The phase difference between two waves, represented by y_1 = 10^ … - Vidyadip

MCQ

The phase difference between two waves, represented by ${y_1} = {10^{ - 6}}\sin \left\{ {100t + \left( {x/50} \right) + 0.5} \right\}\ m$ , ${y_2} = {10^{ - 6}}\cos \left\{ {100t + \left( {\frac{x}{{50}}} \right)} \right\}\ m$ where $x$ is expressed in metres and $t$ is expressed in seconds, is approximately .... $radians$

A
$2.07$
B
$0.5$
C
$1.5$
✓
$1.07$

✓

Answer

Correct option: D.

$1.07$

d
$\Delta \phi=\frac{\pi}{2}-0.5$

$=1.07$ radian.

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